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Module VI: Basics of Semiconductor Physics

1. Introduction to Semiconductors

Semiconductor
A material whose electrical conductivity lies between that of conductors (metals) and insulators. The conductivity can be controlled by temperature, impurities (doping), or light. Examples: Silicon (Si), Germanium (Ge), Gallium Arsenide (GaAs).

The key to understanding semiconductors lies in their band structure – the arrangement of allowed and forbidden energy levels for electrons in the solid.

Energy Band Diagrams: Comparison
Conductor Conduction Band Valence Band Overlapping or no gap Semiconductor Conduction Band Valence Band Eg ~ 1 eV Small band gap (0.5-3 eV) Insulator Conduction Band Valence Band Eg > 5 eV Large band gap (> 5 eV) ■ Conduction Band (empty or partially filled) ■ Valence Band (filled with electrons)
Property Conductor Semiconductor Insulator
Band Gap (Eg) 0 or overlapping 0.5 - 3 eV > 5 eV
Conductivity (σ) 10⁶ - 10⁸ S/m 10⁻⁶ - 10⁴ S/m < 10⁻¹⁰ S/m
Resistivity (ρ) 10⁻⁸ - 10⁻⁶ Ω·m 10⁻⁴ - 10⁶ Ω·m > 10¹⁰ Ω·m
Temp. dependence σ decreases with T σ increases with T σ slightly increases
Examples Cu, Ag, Al Si, Ge, GaAs Diamond, Glass, Rubber

2. Direct and Indirect Band Gap Semiconductors

The band gap is not just characterized by its energy but also by the momentum relationship between the valence band maximum and conduction band minimum. This determines how electrons transition between bands.

Direct Band Gap

The conduction band minimum and valence band maximum occur at the same momentum (k-value).

  • Electron can transition directly by absorbing/emitting a photon
  • No change in momentum required
  • Efficient light emission → used in LEDs, lasers
  • Examples: GaAs, InP, GaN, CdS
Indirect Band Gap

The conduction band minimum and valence band maximum occur at different momentum values.

  • Transition requires both photon AND phonon (lattice vibration)
  • Momentum change needed (provided by phonon)
  • Inefficient light emission → not good for LEDs
  • Examples: Si, Ge
E-k Diagrams: Direct vs Indirect Band Gap
Direct Band Gap (GaAs) k E CB VB Eg = 1.42 eV Indirect Band Gap (Si) k E CB min VB max + phonon Eg = 1.12 eV
Why Does This Matter?
  • Optoelectronics: Direct band gap materials (GaAs, GaN) are used for LEDs and laser diodes because electron-hole recombination efficiently produces photons
  • Solar Cells: Both types work, but direct band gap absorbs light more efficiently for thinner cells
  • Silicon dominates electronics: Despite being indirect, Si is abundant and has excellent oxide (SiO₂) for transistors
Property Direct Band Gap Indirect Band Gap
Transition Photon only Photon + Phonon
Light Emission Efficient (radiative) Inefficient (mostly non-radiative)
Light Absorption High absorption coefficient Lower absorption coefficient
LED/Laser use Excellent Poor
Examples GaAs, InP, GaN, CdTe Si, Ge

3. Electrical Conductivity of Semiconductors

In semiconductors, electrical conduction occurs through two types of charge carriers: electrons in the conduction band and holes in the valence band.

Hole
When an electron leaves the valence band, it leaves behind an empty state called a hole. This hole behaves like a positive charge carrier with positive effective mass, moving in the opposite direction to electrons under an applied field.
σ = n·e·μₑ + p·e·μₕ = e(nμₑ + pμₕ)
Total Conductivity of Semiconductor

Where:

Intrinsic Semiconductor

A pure semiconductor with no impurities. At T > 0 K, thermal energy excites some electrons from valence to conduction band, creating equal numbers of electrons and holes:

n = p = nᵢ (intrinsic carrier concentration)
σᵢ = nᵢ·e·(μₑ + μₕ)
Intrinsic Conductivity
Example: Conductivity Calculation
Intrinsic silicon at 300 K has nᵢ = 1.5 × 10¹⁶ m⁻³, μₑ = 0.135 m²/V·s, μₕ = 0.048 m²/V·s. Calculate the intrinsic conductivity.
Step 1: Use intrinsic conductivity formula
σᵢ = nᵢ·e·(μₑ + μₕ)
Step 2: Substitute values
σᵢ = 1.5 × 10¹⁶ × 1.6 × 10⁻¹⁹ × (0.135 + 0.048)
σᵢ = 1.5 × 10¹⁶ × 1.6 × 10⁻¹⁹ × 0.183
σᵢ = 4.39 × 10⁻⁴ S/m
Intrinsic conductivity σᵢ = 4.39 × 10⁻⁴ S/m (very low – that's why pure Si is a poor conductor)

4. Drift Velocity, Mobility, and Conductivity

4.1 Drift Velocity

Drift Velocity (vd)
The average velocity acquired by charge carriers (electrons or holes) in a material when an external electric field is applied. Without a field, carriers move randomly with zero net velocity.
Random Motion vs Drift Motion
No Electric Field Random motion, no net drift v_avg = 0 With Electric Field E E Random + Drift motion v_d = μE (net drift) e⁻

4.2 Mobility

Mobility (μ)
The drift velocity acquired per unit electric field. It measures how easily charge carriers move through the material. Higher mobility means better conductor.
μ = vd / E
Definition of Mobility (m²/V·s)

Therefore: vd = μE

Factors Affecting Mobility
  • Temperature: Higher T → more lattice vibrations → more scattering → lower mobility
  • Impurity concentration: More impurities → more scattering → lower mobility
  • Effective mass: Lighter carriers have higher mobility
  • Crystal structure: Determines scattering mechanisms

4.3 Relation Between Conductivity and Mobility

Derivation of Conductivity Formula

Current density J = charge × number density × drift velocity

J = n·e·vd (for electrons)

Using vd = μE:

J = n·e·μE

Since J = σE (Ohm's law):

σE = n·e·μE
σ = n·e·μ
σ = n·e·μ
Conductivity (single carrier type)
ρ = 1/σ = 1/(n·e·μ)
Resistivity
Material Electron Mobility μₑ (m²/V·s) Hole Mobility μₕ (m²/V·s)
Silicon (Si) 0.135 0.048
Germanium (Ge) 0.39 0.19
Gallium Arsenide (GaAs) 0.85 0.04
Example: Drift Velocity and Current
A silicon bar with electron concentration n = 5 × 10²¹ m⁻³ and μₑ = 0.135 m²/V·s has an electric field of 100 V/m applied. Calculate: (a) drift velocity (b) current density (c) conductivity.
Step 1: Calculate drift velocity
vd = μₑ × E = 0.135 × 100 = 13.5 m/s
Step 2: Calculate current density
J = n·e·vd = 5×10²¹ × 1.6×10⁻¹⁹ × 13.5
J = 1.08 × 10⁴ A/m²
Step 3: Calculate conductivity
σ = n·e·μₑ = 5×10²¹ × 1.6×10⁻¹⁹ × 0.135
σ = 108 S/m
vd = 13.5 m/s, J = 1.08 × 10⁴ A/m², σ = 108 S/m

5. Fermi-Dirac Distribution Function

Electrons in solids follow Fermi-Dirac statistics because they are fermions (particles with half-integer spin that obey the Pauli exclusion principle). The Fermi-Dirac distribution gives the probability that an energy state E is occupied by an electron.

f(E) = 1 / [1 + exp((E - Eғ) / kT)]
Fermi-Dirac Distribution Function

Where:

Fermi Level (Eғ)
The energy level at which the probability of occupation is exactly 50%. It represents the electrochemical potential of electrons in the material and is a crucial parameter for understanding semiconductor behavior.
Fermi-Dirac Distribution at Different Temperatures
Energy E f(E) 1 0 0.5 T = 0 K T = 300 K T = 600 K All states filled All states empty
Key Properties of Fermi-Dirac Distribution
  • At T = 0 K: f(E) = 1 for E < Eғ, f(E) = 0 for E > Eғ (step function)
  • At E = Eғ: f(Eғ) = 0.5 at all temperatures
  • For E >> Eғ: f(E) → 0 (states mostly empty)
  • For E << Eғ: f(E) → 1 (states mostly filled)
  • Higher T: Distribution becomes more gradual (thermal smearing)
Physical Interpretation

At T = 0, electrons fill all states from the lowest energy up to Eғ. As temperature increases, some electrons gain thermal energy and can occupy states above Eғ, leaving holes below Eғ. The Fermi-Dirac function describes this thermal excitation probability.

6. Position of Fermi Level in Semiconductors

6.1 Intrinsic Semiconductor

In a pure (intrinsic) semiconductor, the number of electrons in the conduction band equals the number of holes in the valence band: n = p = nᵢ.

Fermi Level in Intrinsic Semiconductor
Ec Conduction Band Ev Valence Band Band Gap (Eg) Eғ (≈ middle) electrons (n) holes (p) n = p = nᵢ
Eғ = (Ec + Ev)/2 + (3kT/4)ln(mₕ*/mₑ*)
Fermi Level in Intrinsic Semiconductor

If mₕ* ≈ mₑ* (effective masses approximately equal):

Eғ ≈ (Ec + Ev)/2 = Ec - Eg/2
Fermi Level at center of band gap

6.2 Extrinsic Semiconductor (n-type)

When a semiconductor is doped with donor impurities (e.g., P, As, Sb in Si), extra electrons are introduced. The Fermi level shifts toward the conduction band.

Fermi Level in n-type Semiconductor
Ec Ed (donor level) Ev Many electrons (n >> nᵢ) Few holes (p << nᵢ) Eғ shifts toward Ec
Eғ = Ec - kT·ln(Nc/Nd)
Fermi Level in n-type (Nd = donor concentration)

6.3 Extrinsic Semiconductor (p-type)

When doped with acceptor impurities (e.g., B, Al, Ga in Si), holes are introduced. The Fermi level shifts toward the valence band.

Fermi Level in p-type Semiconductor
Ec Ev Ea (acceptor level) Few electrons Many holes (p >> nᵢ) Eғ shifts toward Ev
Eғ = Ev + kT·ln(Nv/Na)
Fermi Level in p-type (Na = acceptor concentration)
Type Dopant Majority Carrier Fermi Level Position
Intrinsic None (pure) n = p = nᵢ Middle of band gap
n-type Donor (P, As, Sb) Electrons (n >> p) Closer to Ec
p-type Acceptor (B, Al, Ga) Holes (p >> n) Closer to Ev
Example: Fermi Level Position
Silicon at 300 K has Eg = 1.12 eV. If it is doped with donors such that n = 10²² m⁻³ and Nc = 2.8 × 10²⁵ m⁻³, find the position of Fermi level below Ec.
Step 1: For n-type, n ≈ Nd (at room temperature)
Eғ = Ec - kT·ln(Nc/n)
Step 2: Calculate kT at 300 K
kT = 1.38 × 10⁻²³ × 300 = 4.14 × 10⁻²¹ J = 0.0259 eV
Step 3: Calculate Ec - Eғ
Ec - Eғ = kT·ln(Nc/n) = 0.0259 × ln(2.8 × 10²⁵ / 10²²)
Ec - Eғ = 0.0259 × ln(2800) = 0.0259 × 7.94
Ec - Eғ = 0.206 eV
Fermi level is 0.206 eV below the conduction band edge
Temperature Dependence
  • At low T: Fermi level is close to the dopant level (Ed or Ea)
  • At moderate T: All dopants ionized, Eғ between dopant level and intrinsic position
  • At high T: Intrinsic carriers dominate, Eғ moves toward middle of band gap

Summary: Key Formulas

σ = e(nμₑ + pμₕ)
Total Conductivity
vd = μE
Drift Velocity
σ = neμ
Conductivity-Mobility Relation
f(E) = 1/[1 + exp((E-Eғ)/kT)]
Fermi-Dirac Distribution
Eғ(intrinsic) ≈ (Ec + Ev)/2
Intrinsic Fermi Level
np = nᵢ²
Mass Action Law
Key Concepts Summary
  • Direct vs Indirect Band Gap: Direct allows efficient light emission; Indirect requires phonon assistance
  • Conductivity: Depends on carrier concentration and mobility
  • Mobility: Drift velocity per unit field; affected by scattering
  • Fermi-Dirac: Probability distribution for electron occupancy
  • Fermi Level: 50% occupancy level; shifts with doping
  • n-type: Donor doping, Eғ near Ec, electrons are majority carriers
  • p-type: Acceptor doping, Eғ near Ev, holes are majority carriers